Math, asked by Tontry, 1 year ago

(tanA+secA-1)/(tanA-secA+1)= tanA+secA​

Answers

Answered by rajdeepshaw968
2

Answer:

The question is wrong.

Step-by-step explanation:

(tanA+secA-1)/(tanA-secA+1)=1)tanA+secA.

This is right answer.

Answered by shashwatjha2002
1

Answer:y = Sin log x

Here, Differentiate w.r.t x by using first derivative

dy/dx = d/dx [Sin log x]

= cos (logx) . d/dx (log x)

= 1/x cos (log x)

Step-by-step explanation:

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