(tanA+secA-1)/(tanA-secA+1)= tanA+secA
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Answered by
2
Answer:
The question is wrong.
Step-by-step explanation:
(tanA+secA-1)/(tanA-secA+1)=1)tanA+secA.
This is right answer.
Answered by
1
Answer:y = Sin log x
Here, Differentiate w.r.t x by using first derivative
dy/dx = d/dx [Sin log x]
= cos (logx) . d/dx (log x)
= 1/x cos (log x)
Step-by-step explanation:
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