Question

tanA+secA-1/tanA-secA+1=tanA+secA

Answer 1

heya...!!!

we know that:-

1 + tan²A = sec²A

=> 1 = sec²A - tan²A




$\frac{tana + seca - 1}{tana - seca + 1} \\ \\ = > \frac{tana + seca - ( {seca}^{2} - {tan}^{2} a) }{tana - seca + 1} \\ \\ = > \frac{(tana + seca) - (seca - tana)(seca + tana)}{tana - seca + 1} \\ \\ = > \frac{(tana + seca)(1 - seca + tana)}{(tana - seca + 1)} \\ \\ = > tana + seca$

Answer 2

Answer:

your answer attached in the photo