Question

(tanA-secA) (tanA+secA) =

Answer 1

Answer:

$\huge\mathcal{\boxed{\pink{heya!! :) }}}$

$(tanA) {^2}-(secA) {^2}$

Answer 2

Answer:

-1

Step-by-step explanation:

(tanA-secA)(tanA+secA)

=tan²A-sec²A [because (a+b)(a-b)=a²-b²] =-(sec²A-tan²A)

=-1 [because sec²A-tan²A=1]