Question

TanA+secA=x then find the value of tanA-secA

Answer 1

$\huge\boxed{\huge\boxed{\huge\boxed{\bold{ \ \ \ \ \ \ \ \ \ \ \ \ \ ANSWER:\ - \ \frac{1}{x} \ \ \ \ \ \ \ \ \ \ \ \ \ }}}}$

==============================================================

$\bold{\sec^2A-\tan^2A=1} \\ \\ \bold{(\sec A+\tan A)(\sec A - \tan A)=1} \\ \\ \bold{(\tan A+\sec A)(\sec A + \tan A)}=1 \\ \\ \bold{x(\sec A - \tan A)}=1 \\ \\ \bold{\sec A - \tan A=\frac{1}{x}} \\ \\ \bold{-(\sec A - \tan A)=-\frac{1}{x}} \\ \\ \bold{-\sec A + \tan A =-\frac{1}{x}} \\ \\ \bold{\tan A - \sec A = -\frac{1}{x}}$

==============================================================

$\huge\boxed{\huge\boxed{\bold{\ \ \ \ \ \ \ \ \ \ \ \ \ \ THANK\ YOU. \ \ \ \ \ \ \ \ \ \ \ \ \ \ }}}$