Question

tanA+secA=x, then prove that sinA=x²-1/x²+1. Plz help

Answer 1

heya

tanA+SecA=x _-----------1)

then ,1/x=1/tanA+secA×tanA-secA/tanA-secA

=tanA-secA/tan^2A-sec^2A

=tanA-secA/-1 (sec^2A-tan^2A=1)

-tanA+secA =1/x .""""':'''''''11)

now,a adding both equation then..1)and 11)

we get .2secA=x^2+1/x^2 --------111)

and and 2tanA=x^2-1/x^2-----1111)

now dividend both equation 111)and 11111)

we get, sinA=x^2-1/x^2+1 .

hope it help you..

@rajukumar.