tanA× sinA+cosA= secA
Answers
Answered by
16
tanA×SinA+cosA=secA
LHS=tanA×SinA+CosA
=(sinA/cosA)×sinA+cosA [tanA=SinA/CosA]
=sinA^2/cosA+cosA
=(sinA^2+cosA^2)/cosA
=1/cosA [sinA^2+cosA^2=1]
=secA=RHS
hope this will helps
LHS=tanA×SinA+CosA
=(sinA/cosA)×sinA+cosA [tanA=SinA/CosA]
=sinA^2/cosA+cosA
=(sinA^2+cosA^2)/cosA
=1/cosA [sinA^2+cosA^2=1]
=secA=RHS
hope this will helps
vinudeepu137:
tq u so much
np anytime
it's correct. .so pls mark me as brainlist
sry bro or sis.....i dont know how to make u as brainlist
Similar questions