tanA.sinA+cosA=secA how you prove it
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Here is your ans. Hope this will help you
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We have,
=> tanA.sinA + cosA = sec A
Solving L.H.S.
=> tanA.sinA + cosA
=> 1/cosA(sin²A + cos²A)
=> secA
Q.E.D.
=> tanA.sinA + cosA = sec A
Solving L.H.S.
=> tanA.sinA + cosA
=> 1/cosA(sin²A + cos²A)
=> secA
Q.E.D.
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