Math, asked by keerthanakichu39, 2 months ago

tanA-sinA/sin^2A=tanA/1+cosA

Answers

Answered by soniakatariask

0

Answer:

tana-sina/sin²a=((sina/cosa)-sina)/sin²a

sina-sinacosa/cosasin²a

sina(1-cosa)/cosa(1-cos²a)

tana/1+cosa hence proved plz mark me brainles

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