Question

tanA-sinA/sin^2A=tanA/1+cosA

Answer 1

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Answer 2

L.H.S = tan A - sin A/(sin^2A)

= (sin A/cos A - sin A)/(sin^2A)

= (sin A - sin A.cos A/cos A)/(sin^2A)

= {sin A/cos A(1 - cos A)}/(sin^2A)

={tan A(1 - cos A/sin^2A)}

= {tan A[(1 - cos A)(1 + cos A)/(sin^2A)(1 + cos A)]}

= {tan A[(1 - cos^2A)/(sin^2A)(1 + cos A)]}

= {tan A[(sin^2A)/(sin^2A)(1 + cos A)]}

= tan A/(1 + cos A)

= R.H.S

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