Question

tanA(sinA) = tanA+sinA​

Answer 1

Answer:

please mark as brainlist

Step-by-step explanation:

this cannot be proved

Answer 2

Answer:

tanA×sinA=tanA+sinA

(tanA = sinA/cosA)

(sinA/cosA)×sinA=(sinA/cosA)+sinA

sin²A/cosA = (sinA+cosA×sinA)/cosA

sin²A = sinA+cosA×sinA

sin²A = sinA(1+cosA)

sinA = 1+cosA

sinA-cosA = 1

it can be possible only when A = 90 as sin90 = 1 and cos90 = 0 so,

sin90-cos90 = 1

A = 90

I hope it helps you :-)

please mark me as brainliest....