Math, asked by jitesh08, 1 year ago

tanA+sinA/tanA-sinA=secA+1/secA-1

Answers

Answered by Anonymous
7
tanA +sinA/ tanA- sinA= secA+1 /secA-1

LHS
tanA +sinA/ tanA- sinA

=tanA/sinA

=secA

R.HS

secA+1/secA-1
secA/1
=secA


LHS=RHS proved

Answered by 1231221
20

Hi

Dear student there is proper explanation in the attachment.

Attachments:
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