Math, asked by TarekKoo, 5 months ago

tanA - tan2A + sec2A =senA + COS A​

Answers

Answered by smArora
1

Answer:

LHS=sinA+cosAcosA−sinA. =(sinA+cosA)2(cosA−sinA)(cosA+sinA) =sin2 A+cos2A+2sinAcosAcos2A−sin2A.

LHS=sinA+cosAcosA−sinA =(sinA+cosA)2(cosA−sinA)(cosA+sinA) =sin2A+cos2A+2sinAcosAcos2A−sin2A ...  More

It seemed easier to start from the right; please see proof below. Explanation: We need the ...  More

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