Math, asked by ritika1718, 1 year ago

TanA+tan2B+root3tan Atan2A=root3

Answers

Answered by Swarup1998

⛤HERE IS YOUR ANSWER⛤

$tan \alpha + tan2 \alpha + \sqrt{3} \: tan \alpha \: tan2 \alpha = \sqrt{3} \\ or \: \: tan \alpha + tan2 \alpha = \sqrt{3} (1 - tan \alpha \: tan2 \alpha ) \\ or \: \: \frac{tan \alpha + tan2 \alpha }{1 - tan \alpha \: tan \: 2 \alpha } = \sqrt{3} \\ or \: \: tan( \alpha + 2 \alpha ) = \sqrt{3} \\ or \: \: tan3 \alpha = \sqrt{3} = tan \frac{\pi}{3} \\ or \: \: 3 \alpha = \frac{\pi}{3} \\ or \: \: \alpha = \frac{\pi}{9} \\ \\ hence \: \: \alpha = \frac{\pi}{9}$

⛤HOPE THIS ⬆ HELPS YOU⛤

ritika1718: It’s lil difficult to read it out but it’s ok

Thankxxx

Swarup1998: why?? it is clear... i just put alpha instead of A

ritika1718: No no it’s clear but u have written it like a paragraph ....that’s why

Swarup1998: Oo... i should have used enter button twice... i used it once

ritika1718: Okay

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