tanA + TanB)/cotA + cotB = TanA+TanB
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Answer:
To Prove:
tanA+cotB
tanA+tanB
=tanA.tanB
L.H.S
=
tanA
1
+
tanB
1
tanA+tanB
=
tanA.tanB
tanB+tanA
tanA+tanB
[∵ tanA=
cosA
1
]
=tanA.tanB=R.H.S
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