tanA-tanB=sin(a-b)÷cosAcosB
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Answer:
sin(A+B) / cosacosB ? tanA + tanB
sin(A+B) = sinAcosB + cosAsinB (identity learnt in 10th or 11th grade just trust me on this.)
sin(A+B) / cosacosB = (sinAcosB + cosasinB) / (cosAcosB)
= sinAcosB/cosAcosB + cosAsinB/cosAcosB
= sinA/cosA + sinB/cosB
= tana + tanB
Explanation:
THIS ANSWER IS ASSUMING THAT THE sin( a + b ) was a typo and the only angles are A & B
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