tanA*tanB + tan A*cotB
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Answered by
0
answer.....
2tanA by sin2B
2tanA by sin2B
Answered by
2
Hello there!!!
Here's the answer to your question
tanA tanB + tan A cotB
= tanA (tanB + cotB)
=tanA (tanB + 1/tanB)
=tanA (tan^2B + 1)/tanB
= {tanA(tan^2B +1)} / tanB
HOPE THAT HELPS ☺️
Here's the answer to your question
tanA tanB + tan A cotB
= tanA (tanB + cotB)
=tanA (tanB + 1/tanB)
=tanA (tan^2B + 1)/tanB
= {tanA(tan^2B +1)} / tanB
HOPE THAT HELPS ☺️
RoshanSingh1:
tanA (sec ”2B/tanB)
yep
further simplification
✌️
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