TanA + TanB + TanC = 6
TanA TanB = 2
The triangle is?
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sippi:
In ∆ABC
Agnelprinson
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Answered by
33
A+B+C=180
A+B=180-C
Tan(A+B)=-TanC
(TanA+TanB)/(1-TanATanB)=-TanC
TanA+TanB+TanC=TanATanBTanC=6
TanC=3. so the angle C is acute.
TanA+TanB=3
TanA-TanB=1
therefore TanA=2 and TanB=1
A and B are also
acute
So this triangle is acute triangle.
A+B=180-C
Tan(A+B)=-TanC
(TanA+TanB)/(1-TanATanB)=-TanC
TanA+TanB+TanC=TanATanBTanC=6
TanC=3. so the angle C is acute.
TanA+TanB=3
TanA-TanB=1
therefore TanA=2 and TanB=1
A and B are also
acute
So this triangle is acute triangle.
plz mark as d bst.
Tq very much pls ans another question if possible
Why will it become acute if tan C =3?
Say fast pls
Answered by
7
Why is it acute when c is 3?
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