Math, asked by krissvyas999, 8 months ago



tanA+tanB+tanC=tanA*tanB*tanC​

Answers

Answered by tanusingh87
2

Answer:

tanA+tanB+tanC=tanA*tanB*tanC

Answered by quantumglobe
2

Answer:

For any triangle the sum of the angles is equal to 180 degrees. If we take a triangle ABC, A + B + C = 180 degrees.

A + B + C = 180 or A + B = 180 - C

tan (A + B) = tan (180 - C) = tan C

=> (tan A + tan B)/(1 - tan A*tan B) = tan C

=> tan A + tan B = tan C - tan A*tan B*tan C

=> tan A + tan B + tan C = tan A*tan B*tan C

This proves that tan A + tan B + tan C = tan A*tan B*tan C

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