Math, asked by akhilxnamdev, 10 months ago

tanA =
$2xy \x2 - y2$
SinA =?
CosA =?

Please help me!
Class 9th Math ex. 3.3 que. 11

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Answers

Answered by graphicdesignvidhya

0

Answer:

$sinA=2xy\\cosA=x^{2}-y^{2}$

Step-by-step explanation:

$tanA=\frac{2xy}{x^{2}-y^{2} } \\$

$tanA=\frac{sinA}{cosA} \\$

Therefore,

$sinA=2xy\\cosA=x^{2}-y^{2}$

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