Question

tanA =
$2xy \x2 - y2$
SinA =?
CosA =?



Please help me!
Class 9th Math ex. 3.3 que. 11​

Answer 1

Answer:

$sinA=2xy\\cosA=x^{2}-y^{2}$

Step-by-step explanation:

$tanA=\frac{2xy}{x^{2}-y^{2} }$

$tanA=\frac{sinA}{cosA}$

Therefore,

$sinA=2xy\\cosA=x^{2}-y^{2}$