Question

Tanay and Vihaan together have 50 sweets. Both of them ate up 5 sweets
each, and the product of the number of sweets they now have is 351.
We need to find out how many sweets each of them had to start with
​

Answer 1

Answer:

Let the number of sweets with tanay be X .

Let the number of sweets with vihaan be Y .

Therefore, according to condition 1

X+Y = 50

X = 50-Y

Let the above given equation be 1 .

It is given that both of them eat up their five sweets

Therefore , the sweets left with tanay will be X-5 and with vihaan will be Y-5 .

According to condition 2 ,

(X-5) x (Y-5) = 351

There fore ,

XY -5X -5Y + 25 = 351

(50-Y)Y - 50 + Y - 5Y = 326

50Y - Y² + Y - 5Y = 376

-Y² + 46Y = 376

Y² - 46Y + 376 = 0

Now we need to solve it by quadratic equation formula method to get the answer