tanay cycle to school at an average speed of 14 km/h and reacjes school in half an hour . hpw long will he take to reach the schoolof he cycles at an average speed of 15km/h ?
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20
Tanay takes half an hour to reach his school at the speed of 14kmph.
speed=14kmph. time =30minutes=0.5hours.
distance = speed×time.
= 14× 0.5
= 7km.
So the distance between between Tanay and his school is 7km.
Now he has to travel at the speed of 15 kmph for 7km , time taken = distance / speed.
speed = 15 kmph . distance =7km.
time taken = 7 / 15 => 0.46hours.
speed=14kmph. time =30minutes=0.5hours.
distance = speed×time.
= 14× 0.5
= 7km.
So the distance between between Tanay and his school is 7km.
Now he has to travel at the speed of 15 kmph for 7km , time taken = distance / speed.
speed = 15 kmph . distance =7km.
time taken = 7 / 15 => 0.46hours.
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2
Step-by-step explanation:
- 14/30 15/y
- 14×30 =50×y
- y= 14×30/15
- y= 420/15
- y= 28.
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