tanaya covers a part of the journey at 60 km/h and the balance at 40 km per hour talking a total of 5 hours to cover a distance of 240 km. for how many hours did he drive at 40 km per hour.
Answers
answer:
he velocity of car which is overtaking v
1
=60×
18
5
=50/3m/s
The velocity of car to be overtaken v
2
=42×
18
5
=35/3m/s
The relative velocity between them v
12
=v
1
−v
2
=
3
50
−
3
35
=5m/s
The distance traveled by car 1 in overtaking car 2 = 10 m
∴Time taken in overtaking this distance =
5
10
=2s
The distance travelled by car 1 in this duration
s=
3
50
×2=33.3 m
The total distance used for overtake=s+5=33.3+5=38.5 m
plz make me brainlizt
he travelled 3 hr at the speed of 40 kmph
Step-by-step explanation:
Suppose x hr he travelled at 40 kmph
So 5-x hr he travelled at 60 kmph
According to the question,
40x + 60(5-x) = 240
40x -60x +300 = 240
20x = 60
x = 3 hr
Thus he travelled 3 hr at the speed of 40 kmph.