Question

tance covered by the car during this time.
A car starts from rest and moves with a constant accelera.
ton. During the 5th second of its motion, it covers a distance of 36
metres. Calculate (a) the acceleration of the car (b) the total distance covered by the car during this time​

Answer 1

Explanation:

a) Snth=u+a(n-1/2)

0+a(5-1/2)

a(9/2)

9a/2=36

a=72/9

a=8m/s²

b) s= ut+1/at²

(0×5) + 1/2 ×8×5×5

0+100

100m