tane
(ii) 1+
(1 + sec )
= sec 0
(1+tan2ni
Answers
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3
Answer:
LHS =left hand side, RHS =right hand side
LHS
=
1
1
+
sin
θ
+
1
1
−
sin
θ
=
1
−
sin
θ
+
1
+
sin
θ
(
1
+
sin
θ
)
(
1
−
sin
θ
)
->Common Denominator
=
1
−
sin
θ
+
1
+
sin
θ
(
1
+
sin
θ
)
(
1
−
sin
θ
)
=
2
1
−
sin
2
x
=
2
cos
2
x
=
2
⋅
1
cos
2
x
=
2
sec
2
x
=
R
H
S
Step-by-step explanation:
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