Math, asked by abidhassankhan786, 6 months ago

tane
(ii) 1+
(1 + sec )
= sec 0
(1+tan2ni​

Answers

Answered by Anonymous
3

Answer:

LHS =left hand side, RHS =right hand side

LHS

=

1

1

+

sin

θ

+

1

1

sin

θ

=

1

sin

θ

+

1

+

sin

θ

(

1

+

sin

θ

)

(

1

sin

θ

)

->Common Denominator

=

1

sin

θ

+

1

+

sin

θ

(

1

+

sin

θ

)

(

1

sin

θ

)

=

2

1

sin

2

x

=

2

cos

2

x

=

2

1

cos

2

x

=

2

sec

2

x

=

R

H

S

Step-by-step explanation:

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