Question

tangent of curve y = x^2 at x = 0 is
​

Answer 1

Answer:

The equation of tangent: y = 0.

Step-by-step explanation:

The solpe of the tangent is: dy/dx = 2x

At the point, x = 0; dy/dx = 2(0) = 0. That is, the tangent is parallel to the x-axis.

The equation of a line parallel to the x-axis is y = a, where a is the y coordinate through which it passes.

Since, the tangent is drawn at x=0 for the curve y=x², the y coordinate that corresponds to x=0 will be: y=(0)² = 0.

Thus, the equation of the tangent is y=0, which is the x-axis itself.