Question

tangent PQ at a point P of a circle of radius 5cm meets a line through the

centre O at a point Q so that OQ=12cm. Find length of PQ. ​

Answer 1

Answer:

Step-by-step explanation

Given,

Radius OP=5cm and OQ=12cm

PQ is the tangent to the circle.

∠OPQ=90  

0

 

So,by Pythagoras theorem we get,

PQ  

2

=OQ  

2

−OP  

2

 

=>PQ  

2

=12  

2

−5  

2

 

=>PQ  

2

=144−25

=>PQ  

2

=119

=>PQ=  

119

​  

cm

Answer 2

Step-by-step explanation:

Radius OP=5cm and OQ=12cm

PQ is the tangent to the circle.

∠OPQ=90°

So,by Pythagoras theorem we get,

$PQ ^{2} =OQ ^{2} −O P ^{2} </p><p></p><p>PQ ^{2} =12 {}^{2} −5 {}^{2} </p><p></p><p>PQ ^{2} =144−25 </p><p></p><p>PQ {}^{2} =119 </p><p></p><p>PQ= \sqrt{} 119cm</p><p></p><p>$