Tangent to y=5x⁵+10x+15......,Select correct option from the given options.
(a) is always vertical
(b) is always horizontal
(c) makes acute angle with the positive X-axis
(d) makes obtuse angle with the positive X-axis
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answer : option (c) makes acute angle with positive X- axis.
explanation : function, y = 5x⁵+10x+15
differentiating y with respect to x,
dy/dx = 5 d(x⁵)/dx + 10 d(x)/dx + d(15)/dx
= 5 × 4x⁴ + 10 + 0
= 20 x⁴ + 10
here domain of y = y=5x⁵+10x+15 is all real numbers.
I.e., -∞ < x < ∞
⇒0 ≤ x⁴ < ∞
⇒0 ≤ 20x⁴ < ∞
⇒10 ≤ 20x⁴ + 10 < ∞
i.e., dy/dx ≥ 10 , it means slope of tangent of curve always will be positive.
but slope , m = tanθ
and we know, tanθ is positive in two quadrant first and 3rd.
first quadrant, [0, π/2] ⇒an acute angle will form.
but 3rd quadrant [π, 3π/2] ⇒not obtuse angle.
so, the tangent makes acute angle with the positive x-axis.
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