Question

Tangents AP and AQ are drawn to circle with centre o
from an external point A. Prove that LPAQ = 2 LOPQ.​

Answer 1

Step-by-step explanation:

can you repost the question I cant find the point L in the question

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Answer 2

Answer:

Step-by-step explanation:

1) AP=AQ (since the tangents drawn from a external point are equal)

2) angle POA= angle QOA

by RHS congruence we can say that angle A=B=90

and OA=OB=radius

and OP common hypotenuse

so angle angle OAP=1/2PAQ

so PAQ=2OAP

and if you draw a line from P to Q

then it is going to intersect the line OA at X let say

so now angle PXO =90

and POX is also same as angle POA since the same line that means

angle OAP = angle XPO or you can say angle QPO

so

OAP=1/2PAQ

so this

angle PAQ=2OPQ as well