Question

Tangents drawn from the point P(1, 8) to the circle x² + y² –6x– 4y –11 = 0 touch the circle at the points A and B. The equation of the circumcircle of the triangle PAB is
(a) x² + y² + 4x– 6y +19 = 0
(b) x² + y² – 4x – 10y + 19 = 0
(c) x² + y² – 2x + 6y – 29 = 0
(d) x² + y² – 6x – 4y +19 = 0

Answer 1

The equation of the circumcircle of the triangle PAB is

(a) x² + y² + 4x– 6y +19 = 0