Question

Tangents paand pb are drawn to a circle with centre o from a point p outsidethe circle proove that angle opa=angle oam

Answer 1

Sloution:

constitution - join O with P.

prof:
OA = OB (radius of circle)

PA = PB (Tangent drawn from same point on circle are equal)

OP = OP (common side)

=> triangleOAP = traingleOPB (SSS congruence criterion)

so, angle oap = angle obp (C.P.C.T)

Hence, proved