Tangents to a circle at point P and Q on the
circle intersect at a point R. If PQ = 6 and
PR = 5 then the radius of the circle is
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Answer:
radius = √61/2
Step-by-step explanation:
PQR forms a triangle
PQ=6, PR=5, QR= diameter =?
according to pythagoras theorem
QR²=PQ²+PR²
=6² + 5² = 36+25 =61
QR =√61
radius = √61/2
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