Question

Tangents to a circle at point P and Q on the
circle intersect at a point R. If PQ = 6 and
PR = 5 then the radius of the circle is​

Answer 1

Answer:

radius = √61/2

Step-by-step explanation:

PQR forms a triangle

PQ=6, PR=5, QR= diameter =?

according to pythagoras theorem

QR²=PQ²+PR²

      =6² + 5² = 36+25 =61

QR =√61

radius = √61/2