tanh-¹x+ tanh-¹y=tanh-¹x+y÷1+xy
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Answer:
Answer
We have,
x=tanh
−1
y ………..(1)
We know that,
tanh
−1
y=
2
1
log(
1−y
1+y
)
then,
2tanh
−1
y=log(
1−y
1+y
)
log(
1−y
1+y
)=2tanh
−1
y
using equation (1) and we get,
log(
1−y
1+y
)=2x
1−y
1+y
=e
2x
Hence, this is the answer.
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