Question

Tank A has 20 goldfish and tank B has 25 goldfish Both the tanks have the
same number of goldfish with short tail fin. If the percentage d goldfish with
short tail fin in tank B is 36%, find the percentage of goldfish with short tail fin in
tank A.
APPLICATIONS OF PERCENTAGES​

Answer 1

Answer:

Length= 2b m

Height= h= 4m

1) area of the four walls of the room = 2(length+breadth)*h

2(2b+b)*4=120m^2

8*3b=120

b=120/(8*3)

b=5m

Therefore

Breadth=b=5m

Length=2b=2*5=10m

2)area of the floor= length*breadth

=10m*5m

=50m^2

Answer 2

Answer:

45%

Step-by-step explanation:

In tank B goldfish with short tail fin is 36%.

That is,

36% of 25 = 36/100 × 25

=9 fishes in tank B

Question shows that both tanks have same no. of that short tail finned goldfish,so

Tank A also has 9 short tail finned goldfishes

then,

Percentage of the particular fish in tank A =

9/20 × 100 = 45%