Question

tank in the form of a right circular cylinderliner its height is 48 metre and base area is 616 square metre find the TSA of cylinder​

Answer 1

Now, we know that the base of the cylinder is a circle. Hence, use the given area of the circle to find the radius of the cylinder. Then, substitute the values in the formula of the lateral surface of the cylinder, 2πrh and formula of the volume, which is, πr2h, where r is the radius of the cylinder and h is the height of the answer:

Hence, the required answer is 29,568m3.

Step-by-step explanation:

We are given that height of a cylindrical tank is 48m and the base area is 616 sq m.

We know that the base area of the cylindrical is the area of the circle.

Also, the area of a circle is given by πr2, where r is the radius of the circle.

Substitute the values of the area and π=227 to find the radius of the cylindrical tank.

616=227r2⇒r2=616(7)22⇒r2=196⇒r=14 This implies that the radius of the cylindrical tank is 14m.

Now, we will calculate the formula of the lateral surface of the cylinder, by substituting the values in the formula, 2πrh, where r is the radius of the cylinder and h is the height of the cylinder.

A=2(227)14(48)A=4224m2

Now, we will calculate the volume of the cylindrical tank by substituting the values in the formula, πr2h

That is

V=(227)(14)2(48)⇒V=29,568m3 ///// Hence, the required answer is 29,568m3.

Answer 2

Step-by-step explanation:

Given :-

A tank is in the form of a right circular cylinder, its height is 48 metres and base area is 616 square metres.

To find :-

Find the TSA of cylinder ?

Solution :-

Given that

A tank is in the form of a right circular cylinder.

Height of the cylinder (h) = 48 m

Base area of the cylinder = 616 sq.m

Since , the base of the cylinder is in the shape of a circle .

Area of the base of the cylinder

= Area of a circle

= πr²

Therefore, πr² = 616 sq.m

=> (22/7)×r² = 616

=> r² = 616×7/22

=> r² = 28×7

=> r² = 196

=> r = ± √196

=> r = ± 14

Since , r is the radius of the cylinder, it cannot be negative.

Therefore, r = 14 cm

We know that

Total Surface Area of a right circular cylinder (TSA) = 2πr(r+h) sq.units

On substituting these values in the above formula then

=> TSA = 2×(22/7)×14×(14+48) sq.m

=> TSA = (2×22×14×62)/7 sq.m

=> TSA = 2×22×2×62 sq.m

=> TSA = 5456 sq.m

Therefore, TSA = 5456 sq.m

Answer :-

Total Surface Area of the right circular cylinder is 5456 sq.m

Used formulae:-

→ Area of the base of the cylinder = Area of a circle = πr²

→ Total Surface Area of a right circular cylinder (TSA) = 2πr(r+h) sq.units

• r = radius
• h = height
• π = 22/7