Question

Tank P contains 40 litres more water than tank Q. Tank R contains thrice as much water as tank Q. If tank R contains 54 litres water, then how much water does tank P can contain?​

Answer 1

Answer:

x=58

Step-by-step explanation:

x=Tank P

y=Tank Q

z=54L = Tank R

3y= z = 54 L

y = 18 L

x=y+40 = 18 L+40 L = 58 L

Tank P has 58 Literes of water

Answer 2

Step-by-step explanation:

Given: Tank P contains $40L$ more water than Tank Q. Tank R has $3x$ water as Tank Q. Tank R has $54L$ water.

To find: Water in Tank P.

For calculation of water in Tank Q,

We know that Tank P is $x$, Tank Q is $y$ and Tank R is $z$.

We know that $3y=z$

⇒ $3y=54$

⇒$y=\frac{54}{3}$

⇒$y=18L$

For calculation of water in Tank P,

We know that Tank P contains $40L$ more water than Tank Q.

⇒ $x=40 + y$

⇒$x=40+18$

⇒$x=58L$

Tank P has $58L$ of water.