Question

Tanmay had some chocolates with him. He gave one-third of them to Akash and one-fifth of them to Sharad. Tanmay could do so without breaking any chocolate. Which of these could be the number of chocolates Tanmay had in the beginning

Answer 1

Answer:

15,30,45,...

Step-by-step explanation:

Answer should be a multiple of 5 and 3.

As it is divided by both 5 and 3.

Hope it gets me brainliest!

Answer 2

Tanmay had the option of starting with 15, 30, 45, 60, 75, or 90 chocolates.

Assume Tanmay started out with x chocolates.

The issue states that Tanmay gave Akash a third of his chocolates, or  $\frac{x}{3}$chocolates, in total.

Additionally, Tanmay gave Sharad one-fifth of his chocolates, which equals $\frac{x}{5}$ chocolates.

The total amount of chocolates distributed is, therefore,  

($\frac{x}{3}$ + $\frac{x}{5}$) = $\frac{(5x+3x)}{15}$ = $\frac{8x}{15}$.

As a result, x - $\frac{8x}{15}$ = $\frac{7x}{15}$ represents the number of chocolates that Tanmay still has after giving some to Akash and Sharad.

Finding an x value that, when $\frac{7x}{15}$ calculated, gives us a positive integer is the next step.

This requirement must be met for x to be both a multiple of 5 and a multiple of 3. Therefore, x could have one of the following values: 15, 30, 45, 60, 75, 90, and so on.

For more such questions on integers: https://brainly.in/question/10699427

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