Math, asked by amankhedar0, 7 months ago

tannl5° tan25° tan30° tan45° tan65° tan85°

Answers

Answered by Anonymous

8

To find :

Tan5° x tan25° x tan30° x tan45° x tan65° x tan85°

=> Tan5° x tan25° x tan30° x tan45° x tan65° x tan85°

=cot85° x cot65° x tan30° x tan45° x tan65° x tan85°

= [tan(90-θ)=cotθ,cot(90-θ)=tanθ]

= 1 x 1 x tan30° x tan45° [cotθ x tanθ=1]

=(1/√3) x 1

=1/√3

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