Question

tano=4
then
tano
sino trino caso
coso​

Answer 1

Answer:

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Answer 2

| QUESTION |

if tanθ = 4

then find sinθ,cosθ,cosecθ,secθ

★USED FORMULAS★

sec²θ - tan²θ = 1

secθ = ±√1+tan²θ

tanθ = sinθ/cosθ

1/secθ = cosθ

1/sinθ = cosecθ

|★ANSWER★|

Given that

tanθ = 4

We know that

secθ = ±√1 + tan²θ

secθ = ±√1+4²

secθ = ±√1+16

secθ = ±√17

Now,

cosθ = 1/√17

sinθ = √1-cos²θ

sinθ = √1-(1/√17)²

sinθ = √1-1/17

sinθ = 4/17

1/sinθ = cosecθ

cosecθ = 1/4/17

cosecθ = 17/4

all trigonometric ratios in question

sinθ = 4/17

cosθ = 1/√17

tanθ = 4

cosecθ = 17/4

secθ = ±√17

★CONCEPTS USED★

♦ trigonometric ratios

♦ trigonometric identities