Math, asked by artika81, 1 month ago

(tanO+cotO) ² = sec²O+cosec²O = (1+tan²O) (1+cot²O)

Answers

Answered by qg5u5k4vt5

0

LHS= ( tanO + cotO) ^2
= tan2O + cot2O + 2 tanOcotO
=( Sec2O -1) + ( Cosec2O -1 ) + 2
= Sec2O + Cosec2O = RHS

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