Question

tano = p / q psina - qsin / p sin + qcos = p2 q2 / p2 + q2​

Answer 1

Answer:

tanA=p/q

then

sinA=p/√(p²+q²)

cosA=q/√(p²+q²)

=> (psinA-qcosA)/(psinA+qcosA)

= (p²-q²)/(p²+q²)

hope it helps you