Question

Tanø/1+tan²ø=sinø/secø when sec=5/4

Answer 1

SecØ +Tanø=4

SecØ= 4-Tanø

squaring both sides

Sec?Ø= 16+ Tan?Ø- 8 Tanø

1+Tan20=16 + Tan?Ø- 8 Tanø

we get 8 Tan Ø= 15

Tanø=15/8

Tan?Ø= 225/64

Sec?Ø= 1+Tan?

Sec?Ø= 289/64

SecØ =17/8

So Cos@=8/17

Sin?Ø=1-Cos?Ø = 1-64/289 =

Sin?Ø= 225/289

SinØ= 15/17

Cos Ø= 8/17 and Sin Ø= 15/17