Question

tanQ/ 1+ tan2Q + cotQ/ 1+ cot2Q = sinQ/cosQ​

Answer 1

Answer:

$\huge\purple {\mathfrak{Bonjour Mate!}}$

LHS = tan Q + cot Q

= sin Q/cos Q + cos Q/sin Q

= sin² Q + cos²Q/cos Q. sin Q

= 1/sin Q. cos Q

= RHS

LHS = RHS

here, we used the identity :

tan A = sin A/cos A

cot A = cos A/sin A

sin²A+cos²A = 1

Answer 2

Step-by-step explanation:

LHS = tan Q + cot Q

= sin Q/cos Q + cos Q/sin Q

= sin² Q + cos²Q/cos Q. sin Q

= 1/sin Q. cos Q

= RHS

LHS = RHS

here, we used the identity :

tan A = sin A/cos A

cot A = cos A/sin A

sin²A+cos²A = 1