Question

tansquareA+cotsqureA+2=secsquareA×cosecsquareA

Answer 1

hi there !
here is the solution
L.H.S= tan²A+cot²A+2
=tan²A+cot²A+2tanAcotA [since cotA=1/tanA
= (tanA+cotA)²
=(sinA/cosA+cosA/sinA)²
=[(sin²A+cos²A)/sinAcosA]² taking LCM

=[1/sinAcosA]² since sin²A+cos²A=1
=(cosec AsecA)²
=cosec²Asec²=RHS