Question

tanteetha = 1\√3 evaluate cosec square teetha -sec square teetha by cosec square teetha +sec square teetha

Answer 1

let theta = ☆( here )
so tan☆= 1/root3= tan 30
or ☆= 30
now (cosec^2☆-sec^2☆)/(cosec^2☆+sec^2☆)
=(cosec^2 30-sec^2 30)/(cosec^2 30+sec^2 30)
=(4-4/3)/(4+4/3)=1/2....
(since cosec30= 2, sec30=2/root3)