Question

Tantheta/1-cot theta+cot theta/1-tantheta
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Answer 1

hey, is this your question ?

I can't understand what you write

Answer 2

Answer:

1+secθcosecθ.

Step-by-step explanation:

NOTE: im writing Tetha as 0....

tan0/1-cot0 + cot0/1-tan0

we knew,

cot0 = 1/tan0

=tan0/[1-1/tan0] + cot0/1-tan 0

=tan0/[tan0-1/tan0] + cot0/1-tan 0

=tan^2 0/tan0-1 + cot0/1-tan 0

=by LCM

= tan^2 / tan - 1 + cot0/ tan0[tan0-1]

By substituting,

We get 1 + sec0*cosec0