Question

Tantheta/1-cot theta+cot theta/1-tantheta=

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Answer 1

Answer:

(tan theta/1-1/tan theta) + (1/tan theta /1-tan theta)

= tan theta/tan theta -1) + (1/tan theta/1- tan theta)

= (tan² theta/tan theta -1) + (1/tan theta / 1 -tan theta)

= tan ³ theta/than theta -1) -(1/ tan theta (tan theta -1)

= (tan theta) ( tan ² theta +1+ tan theta)/ tan theta(than theta -1)

bez (a³+b³= a² +b² + ab)

=tan² theta + tan theta +1 / tan theta

= tan theta + cot theta + 1

Answer 2

Answer:

1/(Sin2θ - 1)

Step-by-step explanation:

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