Question

tantheta/1-cottheta+cottheta/1-tantheta=1+sectheta.cosectheta​

Answer 1

• Answer:

I hope this will help you

Answer 2

put theta in place of x then we get,

• tanx/1-cotx+cotx/1-tanx
• (sinx/cosx/ 1- cosx/sinx)+(cosx/sinx/1-sinx/cosx)
• (sinx/cosx/sinx-cosx/sinx)+(cosx/sinx/cosx-sinx/cosx)
• (sin^2x/cosx(sinx-cosx))+(cos^2x/sinx(cosx-sinx))
• sin^3x-cos^3x/ sinx.cosx(sinx-cosx)
• (sinx-cosx)(sin^2x+cos^2x+sinxcosx)/sinxcosx(sinx-cosx)
• sin^2x+cos^2x+sinxcosx/ sinxcosx
• 1+sinxcosx/sinxcosx
• 1+secxcosecx

Now replace x by theta

• tantheta/1-cot theta +cot theta/1-tantheta = 1+sectheta cosectheta