Question

tantheta+ sec theta=root 3 then theta is
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Answer 1

$\: \: \: \: \: \: \: \: \: \: \: \: \: \huge\mathcal\pink{\boxed{\boxed{Answer}}}$

$Gɪᴠᴇɴ : \tanθ \: + \secθ = \sqrt{3}$

$Tᴏ \: Fɪɴᴅ : \: ᴠᴀʟᴜᴇ \: ᴏғ \: θ$

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$\tanθ + \secθ = \sqrt{3} = > (1)$

$ʀᴇᴍᴇᴍʙᴇʀɪɴɢ \: ᴛʜᴇ \: ᴛʀɪɢᴏɴᴏᴍᴇᴛʀɪᴄ \: ɪᴅᴇɴᴛɪᴛʏ$

$\: \: \: \: \: \: \: \: \: = > { \secθ }^{2} - { \tanθ }^{2} = 1$

$➺ \: \: ( \secθ + \tanθ) \: ( \secθ - \tanθ) = 1$

$➺ \: \sqrt{3} \times ( \secθ - \tanθ) = 1$

$➺ \: ( \secθ - \tanθ) = \frac{1}{ \sqrt{3} } \: \: = > (2)$

$ʙʏ \: ᴀᴅᴅɪɴɢ \: ᴇϙᴜᴀᴛɪᴏɴ \: (1) \: ᴀɴᴅ \: (2); \: ᴡᴇ \: ɢᴇᴛ,$

$2 \secθ = \sqrt{3} + \frac{1}{ \sqrt{3} }$

$➺2 \secθ = \frac{3 + 1}{\sqrt{3} }$

$➺ \secθ = \frac{4}{ \sqrt{3} \times 2 }$

$➺ \secθ = \frac{2}{ \sqrt{3} }$

$➺ \secθ = \sec30°$

$➺θ = 30°$

$ᴛʜᴇʀᴇғᴏʀᴇ \: \: θ=30°$

Hᴏᴘᴇ Iᴛ Hᴇʟᴘs Yᴏᴜ!

Answer 2

Step-by-step explanation:

hope this helps you dear ♥