tanu covered 2.1/3km in first hour, 1.1/6km in second hour and 2.1/4 km in third hour. find total distance covered by her in three hours
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cover distance of Tanu of first hour=2.1/3 km
distance of second hour=1.1/6 km
distance of third hour=2.1/4km
So, the total of this three
kilometre=2.1/3 + 1.1/6 +2.1/4 km
first find the LCM of denominator (3, 6,4)
LCM=12, denominator must should be same
2.1×4 / 3×4 = 8.4/12
1.1×2 / 6×2 = 2.2/12
2.1×3 / 4×3 = 6.3/12
8.1/12 + 2.2/12 + 6.3/12
21.96/12
we will simplest it
21.96÷2 / 12÷2
=10.98 / 6, again we simplest it
10.98÷2 / 6÷2
=5.49 / 3
also again we simplest it
5.49÷3 / 3÷3
=1.83km
ans. = Tanu covered 1.83 kilometre in 3 hours
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