Question

tanx=2/5 then sin2x equals what

Answer 1

Answer :

Given, tanx = 2/5

∴ sinx = 2/√(2² + 5²) = 2/√29
and cosx = 5/√(2² + 5²) = 5/√29

Now, sin2x

= 2 sinx cosx

= 2 × 2/√29 × 5/√29

= (2 × 2 × 5)/√(29 × 29)

= 20/29 [∵ √(a × a) = a]

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Answer 2

Solution:-

given:-

》 tanx = 2/5

》we know that tanx = hieght/base = 2 , 5

》by trigonometry

》k^2 = 2^2+5^2 = k= (4+25 )^1/2=

》k= root29

》sinx = h/k = 2/root29, cos = 5/root29

》then :-

》sin2x = 2sinx.cosx

= 2×2/root29× 5/root29
》
( sin2x = 20/29)ans
》